Mike Trout wins AL Hank Aaron Award

[Chuck]

Today, Angels outfielder Mike Trout was selected as the American League winner of the 2019 Hank Aaron Award, as announced by Major League Baseball. This is Trout's second Hank Aaron Award recognition, the first being in 2014.

Established in 1999 to honor the 25th anniversary of Aaron breaking Babe Ruth's all-time home run record, the Hank Aaron Awards are officially sanctioned by MLB and recognize the most outstanding offensive performers in each League. Fans voted for the recipients on MLB.com, and for the 10th straight year, a special panel of Hall of Fame players, led by Hank Aaron, joined fans in voting for the Awards.

In his ninth Major League season, Trout led the Majors with a .483 on-base percentage while pacing the American League with a .645 slugging percentage and a 1.083 OPS. Trout, who was named AL Player of the Week for the weeks ending April 7th and June 23rd, ranked second in the AL with a career-best 45 home runs. The two-time AL Most Valuable Player, who earned his eighth consecutive All-Star selection, also ranked second in the AL in WAR (8.3) and runs created (145).

"I would like to extend a sincere thank you to Hank Aaron, the Hall of Famers and fans for this honor," Trout said. "This would not be possible without the support of my teammates, coaches, family and my wife, Jessica. I am humbled and thankful to win this award."

[JustATroutFan]

It’s weird that both times that he won this award, he batted below .300. .287 in 2014 and .291 in 2019. Of course, a big reason why he “only” batted .298 this past year was because of some fluke-like bad luck. A .298 BABIP for Trout, which is low, especially for him. He’s going to hit over .300 again next season with a lot of home runs. 

[AngelsLakersFan]

His stats are incorrect. No wonder he won.